Videos on Handling & Processing of Powder & Bulk Solids
● How to calculate conveyor belt pull
● How to calculate required conveyor drive power
Mike Gawinski states, “An understanding of the basic aspects of conveyor belt pull is essential to properly designing, operating, and maintaining belt conveyors. We will use imperial units in this video. The belt pull required to move packages on a slider bed conveyor equals the total weight of all packages plus the weight of the belt times the coefficient of friction between the bottom of the conveyor belt and the top of the slider bed.”
He continues, “The total weight to be moved, in this example, equals five boxes times 50 pounds per box plus ten feet times 3 pounds per foot, which is 280 pounds. Since the frictional coefficient is 0.5, the belt pull equals 280 pounds times 0.5, which is 140 pounds. We can calculate required power as follows:
140 pounds of belt pull times 50 feet per minute of belt speed equals 7,000 foot pounds per minute.
Since 1 horsepower equals 33,000 foot pounds per minute, the required power equals 7,000 foot pounds per minute divided by 33,000 foot pounds per minute per horsepower or 0.2 horsepower.
Now, it is possible to select an appropriate conveyor drive system to move the packages.”
RULMECA Corporation Videos shown on Powder Bulk Videos:
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